= ∫ cscx − 1 cot2x dx. Let i = ∫ cosec x cos2 (1 + logtan x 2) dxput 1 + logtanx 2 = t⇒ 1 tan x 2.
Integration Of Cosec X Dx. We let u = tanx. We rearrange it for du.
Integration of 1/(x^2 + a^2)^2 YouTube From youtube.com
X d x = log e. X functions with respect to x is written in the following mathematical form in integral calculus. = ∫ cscx −1 csc2x −1 dx.
Integration of 1/(x^2 + a^2)^2 YouTube
Integrate 1 − x 2. = ∫ cscx −1 csc2x −1 dx. The integral of the cosecant of angle x with respect to x is equal to the natural logarithm of the subtraction of cot of angle x from cosecant of angle x, and plus the constant of integration. This is also known as the antiderivative of cosecx.
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This is the calculus part of the question complete, it now remains to show that this solution is equivalent to the given solution; ∫ cosec4xdx= ∫ cosec2x⋅cosec2xdx = ∫ cosec2x(1+cot2x)dx = ∫ (c0sec2x+cot2xcosec2x)dx = ∫ cosec2dx+∫ cot2xcosec2xdx = −cotx+(−∫ t2dt) = −cotx− t3 3 +c = −cotx− cot3x 3 +c ∫ cosec 4. We rearrange it for du. = ln|cscx.
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Int sec^ ( (8)/ (9))x. = ∫( sinx cos2x −sec2x + 1)dx. Cosec^ ( (10)/ (9))x dx`. We rearrange it for du. ∫ 1 1 + cscx dx.
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This is the calculus part of the question complete, it now remains to show that this solution is equivalent to the given solution; 1 2dx = dt⇒ 1 2sin x 2cos x 2 dx = dt⇒ cosecxdx = dt∴ i = ∫ dt cos2t = ∫ sec2tdt= tant + c= tan(1 + logtanx 2) + c. = ∫( sinx cos2x.
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The indefinite integration of product of cosecant and cot functions with respect to x is equal to the sum of negative cosecant function and an integral constant. ∫e dx exx =+ c (xv) 1 log| | d x dx x = ; So consider second function as 1. Hence, we get a new integration expression on the rhs, that means.
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If someone derives $x$, he will get $1$, if he integrates $1$, he will get $x$. ∫ 1 1 + cscx dx. What is 21 by 9 x + conclusion the integral space 2819 x into cos raise to x 9 x x equal to minus 9 race 2 19 x plus. Csc x dx = csc x. 𝑑𝑥〗multiplying and.
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Let i = ∫ cosec x cos2 (1 + logtan x 2) dxput 1 + logtanx 2 = t⇒ 1 tan x 2. Then, du/dx = sec 2 x. This is the calculus part of the question complete, it now remains to show that this solution is equivalent to the given solution; 𝑑𝑥〗multiplying and dividing by 𝑐𝑜𝑠𝑒𝑐 𝑥+𝑐𝑜𝑡 𝑥 f(𝑥)=∫1.
